Optimal. Leaf size=253 \[ \frac {2 A c e (2 c d-b e)-B \left (b^2 e^2-8 b c d e+10 c^2 d^2\right )}{3 e^6 (d+e x)^3}-\frac {A e \left (b^2 e^2-6 b c d e+6 c^2 d^2\right )-B d \left (3 b^2 e^2-12 b c d e+10 c^2 d^2\right )}{4 e^6 (d+e x)^4}+\frac {d^2 (B d-A e) (c d-b e)^2}{6 e^6 (d+e x)^6}+\frac {c (-A c e-2 b B e+5 B c d)}{2 e^6 (d+e x)^2}-\frac {d (c d-b e) (B d (5 c d-3 b e)-2 A e (2 c d-b e))}{5 e^6 (d+e x)^5}-\frac {B c^2}{e^6 (d+e x)} \]
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Rubi [A] time = 0.23, antiderivative size = 253, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {771} \begin {gather*} \frac {2 A c e (2 c d-b e)-B \left (b^2 e^2-8 b c d e+10 c^2 d^2\right )}{3 e^6 (d+e x)^3}-\frac {A e \left (b^2 e^2-6 b c d e+6 c^2 d^2\right )-B d \left (3 b^2 e^2-12 b c d e+10 c^2 d^2\right )}{4 e^6 (d+e x)^4}+\frac {d^2 (B d-A e) (c d-b e)^2}{6 e^6 (d+e x)^6}+\frac {c (-A c e-2 b B e+5 B c d)}{2 e^6 (d+e x)^2}-\frac {d (c d-b e) (B d (5 c d-3 b e)-2 A e (2 c d-b e))}{5 e^6 (d+e x)^5}-\frac {B c^2}{e^6 (d+e x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 771
Rubi steps
\begin {align*} \int \frac {(A+B x) \left (b x+c x^2\right )^2}{(d+e x)^7} \, dx &=\int \left (-\frac {d^2 (B d-A e) (c d-b e)^2}{e^5 (d+e x)^7}+\frac {d (c d-b e) (B d (5 c d-3 b e)-2 A e (2 c d-b e))}{e^5 (d+e x)^6}+\frac {A e \left (6 c^2 d^2-6 b c d e+b^2 e^2\right )-B d \left (10 c^2 d^2-12 b c d e+3 b^2 e^2\right )}{e^5 (d+e x)^5}+\frac {-2 A c e (2 c d-b e)+B \left (10 c^2 d^2-8 b c d e+b^2 e^2\right )}{e^5 (d+e x)^4}+\frac {c (-5 B c d+2 b B e+A c e)}{e^5 (d+e x)^3}+\frac {B c^2}{e^5 (d+e x)^2}\right ) \, dx\\ &=\frac {d^2 (B d-A e) (c d-b e)^2}{6 e^6 (d+e x)^6}-\frac {d (c d-b e) (B d (5 c d-3 b e)-2 A e (2 c d-b e))}{5 e^6 (d+e x)^5}-\frac {A e \left (6 c^2 d^2-6 b c d e+b^2 e^2\right )-B d \left (10 c^2 d^2-12 b c d e+3 b^2 e^2\right )}{4 e^6 (d+e x)^4}+\frac {2 A c e (2 c d-b e)-B \left (10 c^2 d^2-8 b c d e+b^2 e^2\right )}{3 e^6 (d+e x)^3}+\frac {c (5 B c d-2 b B e-A c e)}{2 e^6 (d+e x)^2}-\frac {B c^2}{e^6 (d+e x)}\\ \end {align*}
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Mathematica [A] time = 0.11, size = 257, normalized size = 1.02 \begin {gather*} -\frac {A e \left (b^2 e^2 \left (d^2+6 d e x+15 e^2 x^2\right )+2 b c e \left (d^3+6 d^2 e x+15 d e^2 x^2+20 e^3 x^3\right )+2 c^2 \left (d^4+6 d^3 e x+15 d^2 e^2 x^2+20 d e^3 x^3+15 e^4 x^4\right )\right )+B \left (b^2 e^2 \left (d^3+6 d^2 e x+15 d e^2 x^2+20 e^3 x^3\right )+4 b c e \left (d^4+6 d^3 e x+15 d^2 e^2 x^2+20 d e^3 x^3+15 e^4 x^4\right )+10 c^2 \left (d^5+6 d^4 e x+15 d^3 e^2 x^2+20 d^2 e^3 x^3+15 d e^4 x^4+6 e^5 x^5\right )\right )}{60 e^6 (d+e x)^6} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(A+B x) \left (b x+c x^2\right )^2}{(d+e x)^7} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [A] time = 0.40, size = 340, normalized size = 1.34 \begin {gather*} -\frac {60 \, B c^{2} e^{5} x^{5} + 10 \, B c^{2} d^{5} + A b^{2} d^{2} e^{3} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{4} e + {\left (B b^{2} + 2 \, A b c\right )} d^{3} e^{2} + 30 \, {\left (5 \, B c^{2} d e^{4} + {\left (2 \, B b c + A c^{2}\right )} e^{5}\right )} x^{4} + 20 \, {\left (10 \, B c^{2} d^{2} e^{3} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d e^{4} + {\left (B b^{2} + 2 \, A b c\right )} e^{5}\right )} x^{3} + 15 \, {\left (10 \, B c^{2} d^{3} e^{2} + A b^{2} e^{5} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{2} e^{3} + {\left (B b^{2} + 2 \, A b c\right )} d e^{4}\right )} x^{2} + 6 \, {\left (10 \, B c^{2} d^{4} e + A b^{2} d e^{4} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{3} e^{2} + {\left (B b^{2} + 2 \, A b c\right )} d^{2} e^{3}\right )} x}{60 \, {\left (e^{12} x^{6} + 6 \, d e^{11} x^{5} + 15 \, d^{2} e^{10} x^{4} + 20 \, d^{3} e^{9} x^{3} + 15 \, d^{4} e^{8} x^{2} + 6 \, d^{5} e^{7} x + d^{6} e^{6}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.18, size = 318, normalized size = 1.26 \begin {gather*} -\frac {{\left (60 \, B c^{2} x^{5} e^{5} + 150 \, B c^{2} d x^{4} e^{4} + 200 \, B c^{2} d^{2} x^{3} e^{3} + 150 \, B c^{2} d^{3} x^{2} e^{2} + 60 \, B c^{2} d^{4} x e + 10 \, B c^{2} d^{5} + 60 \, B b c x^{4} e^{5} + 30 \, A c^{2} x^{4} e^{5} + 80 \, B b c d x^{3} e^{4} + 40 \, A c^{2} d x^{3} e^{4} + 60 \, B b c d^{2} x^{2} e^{3} + 30 \, A c^{2} d^{2} x^{2} e^{3} + 24 \, B b c d^{3} x e^{2} + 12 \, A c^{2} d^{3} x e^{2} + 4 \, B b c d^{4} e + 2 \, A c^{2} d^{4} e + 20 \, B b^{2} x^{3} e^{5} + 40 \, A b c x^{3} e^{5} + 15 \, B b^{2} d x^{2} e^{4} + 30 \, A b c d x^{2} e^{4} + 6 \, B b^{2} d^{2} x e^{3} + 12 \, A b c d^{2} x e^{3} + B b^{2} d^{3} e^{2} + 2 \, A b c d^{3} e^{2} + 15 \, A b^{2} x^{2} e^{5} + 6 \, A b^{2} d x e^{4} + A b^{2} d^{2} e^{3}\right )} e^{\left (-6\right )}}{60 \, {\left (x e + d\right )}^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 307, normalized size = 1.21 \begin {gather*} -\frac {B \,c^{2}}{\left (e x +d \right ) e^{6}}-\frac {\left (A \,b^{2} e^{3}-2 A b c d \,e^{2}+A \,c^{2} d^{2} e -B d \,b^{2} e^{2}+2 B \,d^{2} b c e -B \,c^{2} d^{3}\right ) d^{2}}{6 \left (e x +d \right )^{6} e^{6}}-\frac {\left (A c e +2 B b e -5 B c d \right ) c}{2 \left (e x +d \right )^{2} e^{6}}+\frac {\left (2 A \,b^{2} e^{3}-6 A b c d \,e^{2}+4 A \,c^{2} d^{2} e -3 B d \,b^{2} e^{2}+8 B \,d^{2} b c e -5 B \,c^{2} d^{3}\right ) d}{5 \left (e x +d \right )^{5} e^{6}}-\frac {A \,b^{2} e^{3}-6 A b c d \,e^{2}+6 A \,c^{2} d^{2} e -3 B d \,b^{2} e^{2}+12 B \,d^{2} b c e -10 B \,c^{2} d^{3}}{4 \left (e x +d \right )^{4} e^{6}}-\frac {2 A b c \,e^{2}-4 A \,c^{2} d e +B \,b^{2} e^{2}-8 B d b c e +10 B \,d^{2} c^{2}}{3 \left (e x +d \right )^{3} e^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.64, size = 340, normalized size = 1.34 \begin {gather*} -\frac {60 \, B c^{2} e^{5} x^{5} + 10 \, B c^{2} d^{5} + A b^{2} d^{2} e^{3} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{4} e + {\left (B b^{2} + 2 \, A b c\right )} d^{3} e^{2} + 30 \, {\left (5 \, B c^{2} d e^{4} + {\left (2 \, B b c + A c^{2}\right )} e^{5}\right )} x^{4} + 20 \, {\left (10 \, B c^{2} d^{2} e^{3} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d e^{4} + {\left (B b^{2} + 2 \, A b c\right )} e^{5}\right )} x^{3} + 15 \, {\left (10 \, B c^{2} d^{3} e^{2} + A b^{2} e^{5} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{2} e^{3} + {\left (B b^{2} + 2 \, A b c\right )} d e^{4}\right )} x^{2} + 6 \, {\left (10 \, B c^{2} d^{4} e + A b^{2} d e^{4} + 2 \, {\left (2 \, B b c + A c^{2}\right )} d^{3} e^{2} + {\left (B b^{2} + 2 \, A b c\right )} d^{2} e^{3}\right )} x}{60 \, {\left (e^{12} x^{6} + 6 \, d e^{11} x^{5} + 15 \, d^{2} e^{10} x^{4} + 20 \, d^{3} e^{9} x^{3} + 15 \, d^{4} e^{8} x^{2} + 6 \, d^{5} e^{7} x + d^{6} e^{6}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.13, size = 337, normalized size = 1.33 \begin {gather*} -\frac {\frac {x^3\,\left (B\,b^2\,e^2+4\,B\,b\,c\,d\,e+2\,A\,b\,c\,e^2+10\,B\,c^2\,d^2+2\,A\,c^2\,d\,e\right )}{3\,e^3}+\frac {d^2\,\left (B\,b^2\,d\,e^2+A\,b^2\,e^3+4\,B\,b\,c\,d^2\,e+2\,A\,b\,c\,d\,e^2+10\,B\,c^2\,d^3+2\,A\,c^2\,d^2\,e\right )}{60\,e^6}+\frac {x^2\,\left (B\,b^2\,d\,e^2+A\,b^2\,e^3+4\,B\,b\,c\,d^2\,e+2\,A\,b\,c\,d\,e^2+10\,B\,c^2\,d^3+2\,A\,c^2\,d^2\,e\right )}{4\,e^4}+\frac {d\,x\,\left (B\,b^2\,d\,e^2+A\,b^2\,e^3+4\,B\,b\,c\,d^2\,e+2\,A\,b\,c\,d\,e^2+10\,B\,c^2\,d^3+2\,A\,c^2\,d^2\,e\right )}{10\,e^5}+\frac {c\,x^4\,\left (A\,c\,e+2\,B\,b\,e+5\,B\,c\,d\right )}{2\,e^2}+\frac {B\,c^2\,x^5}{e}}{d^6+6\,d^5\,e\,x+15\,d^4\,e^2\,x^2+20\,d^3\,e^3\,x^3+15\,d^2\,e^4\,x^4+6\,d\,e^5\,x^5+e^6\,x^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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